bonsoir,

(x+2)/(2x²+x) - (x-3)/(x²-x) < (10-4x)/(2x²-x-1)
(x+2)/x(2x+1) - (x-3)/x(x-1) - 2(5x-2x)/(x-1)(2x+1) < 0
[(x+2)(x-1)-(x-3)(2x+1)-2x(5-2x)]/[x(2x+1)(x-1)] < 0
(3x²-4x+1)/[x(2x+1)(x-1) < 0
[(x-1)(3x-1)] /[x(2x+1)(x-1) < 0

termine en faisant un tableau de signe

bon courage